![]() Hence, PBr3 has sp3 Hybridization where there is one s and three p hybrid orbitals formed. One can also use the AXN Notation method to find out Hybridization. Finding out the steric number or number of hybrid orbitals is one of the most simplified methods to determine the molecule’s Hybridization. And as there are four hybrid orbitals formed, its Hybridization is sp3. The central atom forms four hybridized orbitals to accommodate all these four pairs of electrons. As mentioned above, there are three bonding pairs and one nonbonding or lone pair of electrons in Phosphorus Tribromide. To find out the Hybridization of the given molecule, we always look at the number of hybridized orbitals formed for the bonds formed as well as the lone pairs of the molecule. There is one lone pair of electrons on the central atom and three sigma bonds in the PBr3 Lewis Structure. For this PBr3 Lewis structure, the charges on the central atom are zero, which suggests that this is the right Lewis dot structure for PBr3. To confirm this structure, one can also calculate the formal charges on the atoms. Place other valence electrons around all the atoms, and here you have the Lewis Structure of PBr3. ![]() As both these atoms now have complete octets. Now, if you notice, forming these bonds will complete the octets of Bromine as well as phosphorus atoms. Each bond here uses up two valence electrons therefore, a total of 6 valence electrons are used up in forming bonds. Here we will first try and complete octets of all Bromine atoms, as each BromineĪtom only requires one valence electron to complete its octet.ĭraw a line between each bromine and phosphorus atom to show bonds. The octet rule says that the atoms with eight valence electrons in their outer shell attain a stable structure. Hence the phosphorus atom will take the central position as the least electronegative atom is placed in the centre.Īll the bromine atoms will be arranged around the central atom-like shown in the figure below:įor drawing a Lewis structure, we always first try and complete the octets of the atoms placed around the central atom. Here we already know that there are 26 valence electrons for PBr3.Īnd Bromine atom is more electronegative than the Phosphorus atom.
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